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Periodic Trends & Inorganic Chemistry (Chemistry) Solved Questions & Notes (2026) - Apex Rankers

Natural & Physical Sciences > Chemistry > Periodic Trends & Inorganic Chemistry

43 Total Solved Questions
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Periodic Trends & Inorganic Chemistry

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Q. 1 Chemistry (Secondary & College Level)
Difficulty: EASY (1 Mark)
Which element on the periodic table has the highest electronegativity value on the Pauling scale (3.98)?
A
Fluorine (F)
✓ Correct
B
Oxygen (O)
C
Chlorine (Cl)
D
Nitrogen (N)
💡 Step-by-Step Explanation & Concept Rationale
Fluorine is the most electronegative element, followed by Oxygen (3.44) and Chlorine/Nitrogen (3.04).
Q. 2 Chemistry (Secondary & College Level)
Difficulty: MEDIUM (1 Mark)
How does the first ionization energy generally change across a period from left to right on the periodic table?
A
It increases due to increasing effective nuclear charge and decreasing atomic radius
✓ Correct
B
It decreases uniformly
C
It remains constant
D
It drops to zero at halogens
💡 Step-by-Step Explanation & Concept Rationale
Across a period, higher proton count pulls electron shells closer, increasing electrostatic hold and raising ionization energy.
Q. 3 Chemistry (Secondary & College Level)
Difficulty: HARD (1 Mark)
Why is the first ionization energy of Nitrogen (Group 15) higher than that of Oxygen (Group 16)?
A
Nitrogen possesses a stable half-filled 2p³ subshell electronic configuration
✓ Correct
B
Nitrogen has a larger atomic radius than oxygen
C
Oxygen has fewer protons than nitrogen
D
Nitrogen is a noble gas
💡 Step-by-Step Explanation & Concept Rationale
Nitrogen's valence configuration (2s² 2p³) features three half-filled degenerate orbitals, providing extra quantum exchange stability compared to Oxygen (2s² 2p⁴).
Q. 4 Chemistry (Secondary & College Level)
Difficulty: EASY (1 Mark)
According to VSEPR theory, what is the geometric molecular shape of a water molecule (H2O)?
A
Linear
B
Bent (Angular)
✓ Correct
C
Tetrahedral
D
Trigonal planar
💡 Step-by-Step Explanation & Concept Rationale
H2O has two bonding pairs and two lone pairs on oxygen, causing repulsion that compresses the tetrahedral angle to a bent shape of 104.5 degrees.
Q. 5 Chemistry (Secondary & College Level)
Difficulty: EASY (1 Mark)
In chemical bonding theory #7: Which type of intermolecular force is responsible for the anomalously high boiling point of water and hydrogen fluoride?
A
Dipole-induced dipole
B
London dispersion forces
C
Hydrogen bonding
✓ Correct
D
Covalent coordinate bonding
💡 Step-by-Step Explanation & Concept Rationale
Hydrogen bonding is a strong dipole-dipole attraction occurring between H bonded to highly electronegative elements (N, O, F).
Q. 6 Chemistry (Secondary & College Level)
Difficulty: EASY (1 Mark)
In chemical bonding theory #12: Which type of intermolecular force is responsible for the anomalously high boiling point of water and hydrogen fluoride?
A
Covalent coordinate bonding
B
London dispersion forces
C
Dipole-induced dipole
D
Hydrogen bonding
✓ Correct
💡 Step-by-Step Explanation & Concept Rationale
Hydrogen bonding is a strong dipole-dipole attraction occurring between H bonded to highly electronegative elements (N, O, F).
Q. 7 Chemistry (Secondary & College Level)
Difficulty: EASY (1 Mark)
In chemical bonding theory #17: Which type of intermolecular force is responsible for the anomalously high boiling point of water and hydrogen fluoride?
A
Hydrogen bonding
✓ Correct
B
London dispersion forces
C
Dipole-induced dipole
D
Covalent coordinate bonding
💡 Step-by-Step Explanation & Concept Rationale
Hydrogen bonding is a strong dipole-dipole attraction occurring between H bonded to highly electronegative elements (N, O, F).
Q. 8 Chemistry (Secondary & College Level)
Difficulty: EASY (1 Mark)
In chemical bonding theory #22: Which type of intermolecular force is responsible for the anomalously high boiling point of water and hydrogen fluoride?
A
London dispersion forces
B
Hydrogen bonding
✓ Correct
C
Dipole-induced dipole
D
Covalent coordinate bonding
💡 Step-by-Step Explanation & Concept Rationale
Hydrogen bonding is a strong dipole-dipole attraction occurring between H bonded to highly electronegative elements (N, O, F).
Q. 9 Chemistry (Secondary & College Level)
Difficulty: EASY (1 Mark)
In chemical bonding theory #27: Which type of intermolecular force is responsible for the anomalously high boiling point of water and hydrogen fluoride?
A
Dipole-induced dipole
B
London dispersion forces
C
Hydrogen bonding
✓ Correct
D
Covalent coordinate bonding
💡 Step-by-Step Explanation & Concept Rationale
Hydrogen bonding is a strong dipole-dipole attraction occurring between H bonded to highly electronegative elements (N, O, F).
Q. 10 Chemistry (Secondary & College Level)
Difficulty: EASY (1 Mark)
In chemical bonding theory #32: Which type of intermolecular force is responsible for the anomalously high boiling point of water and hydrogen fluoride?
A
Covalent coordinate bonding
B
London dispersion forces
C
Dipole-induced dipole
D
Hydrogen bonding
✓ Correct
💡 Step-by-Step Explanation & Concept Rationale
Hydrogen bonding is a strong dipole-dipole attraction occurring between H bonded to highly electronegative elements (N, O, F).
Q. 11 Chemistry (Secondary & College Level)
Difficulty: EASY (1 Mark)
In chemical bonding theory #37: Which type of intermolecular force is responsible for the anomalously high boiling point of water and hydrogen fluoride?
A
Hydrogen bonding
✓ Correct
B
London dispersion forces
C
Dipole-induced dipole
D
Covalent coordinate bonding
💡 Step-by-Step Explanation & Concept Rationale
Hydrogen bonding is a strong dipole-dipole attraction occurring between H bonded to highly electronegative elements (N, O, F).
Q. 12 Chemistry (Secondary & College Level)
Difficulty: MEDIUM (1 Mark)
Which of the following elements has the highest first ionization energy?
A
Fluorine (F)
B
Helium (He)
✓ Correct
C
Neon (Ne)
D
Hydrogen (H)
💡 Step-by-Step Explanation & Concept Rationale
Helium has the highest first ionization energy (2372 kJ/mol) due to its 1s2 stable configuration and minimal shielding.
Q. 13 Chemistry (Secondary & College Level)
Difficulty: EASY (1 Mark)
In inorganic chemistry analysis #7: What color is produced when copper ions (Cu2+) undergo flame test identification?
A
Golden Yellow
B
Crimson Red
C
Blue-Green
✓ Correct
D
Lilac Violet
💡 Step-by-Step Explanation & Concept Rationale
Copper salts produce a characteristic green to blue-green flame due to excitation of electrons in the d-block metal ion.
Q. 14 Chemistry (Secondary & College Level)
Difficulty: EASY (1 Mark)
In inorganic chemistry analysis #12: What color is produced when copper ions (Cu2+) undergo flame test identification?
A
Lilac Violet
B
Crimson Red
C
Golden Yellow
D
Blue-Green
✓ Correct
💡 Step-by-Step Explanation & Concept Rationale
Copper salts produce a characteristic green to blue-green flame due to excitation of electrons in the d-block metal ion.
Q. 15 Chemistry (Secondary & College Level)
Difficulty: EASY (1 Mark)
In inorganic chemistry analysis #17: What color is produced when copper ions (Cu2+) undergo flame test identification?
A
Blue-Green
✓ Correct
B
Crimson Red
C
Golden Yellow
D
Lilac Violet
💡 Step-by-Step Explanation & Concept Rationale
Copper salts produce a characteristic green to blue-green flame due to excitation of electrons in the d-block metal ion.
Q. 16 Chemistry (Secondary & College Level)
Difficulty: EASY (1 Mark)
In inorganic chemistry analysis #22: What color is produced when copper ions (Cu2+) undergo flame test identification?
A
Crimson Red
B
Blue-Green
✓ Correct
C
Golden Yellow
D
Lilac Violet
💡 Step-by-Step Explanation & Concept Rationale
Copper salts produce a characteristic green to blue-green flame due to excitation of electrons in the d-block metal ion.
Q. 17 Chemistry (Secondary & College Level)
Difficulty: EASY (1 Mark)
In inorganic chemistry analysis #27: What color is produced when copper ions (Cu2+) undergo flame test identification?
A
Golden Yellow
B
Crimson Red
C
Blue-Green
✓ Correct
D
Lilac Violet
💡 Step-by-Step Explanation & Concept Rationale
Copper salts produce a characteristic green to blue-green flame due to excitation of electrons in the d-block metal ion.
Q. 18 Chemistry (Secondary & College Level)
Difficulty: EASY (1 Mark)
In inorganic chemistry analysis #32: What color is produced when copper ions (Cu2+) undergo flame test identification?
A
Lilac Violet
B
Crimson Red
C
Golden Yellow
D
Blue-Green
✓ Correct
💡 Step-by-Step Explanation & Concept Rationale
Copper salts produce a characteristic green to blue-green flame due to excitation of electrons in the d-block metal ion.
Q. 19 Chemistry (Secondary & College Level)
Difficulty: EASY (1 Mark)
In inorganic chemistry analysis #37: What color is produced when copper ions (Cu2+) undergo flame test identification?
A
Blue-Green
✓ Correct
B
Crimson Red
C
Golden Yellow
D
Lilac Violet
💡 Step-by-Step Explanation & Concept Rationale
Copper salts produce a characteristic green to blue-green flame due to excitation of electrons in the d-block metal ion.
Q. 20 Chemistry (Secondary & College Level)
Difficulty: MEDIUM (1 Mark)
Le Chatelier's Principle predicts that increasing the pressure on the gaseous equilibrium N2(g) + 3H2(g) <=> 2NH3(g) will:
A
Shift equilibrium to the left
B
Shift equilibrium to the right (favoring NH3 formation)
✓ Correct
C
Have no effect on equilibrium
D
Decrease the rate of forward reaction
💡 Step-by-Step Explanation & Concept Rationale
Increasing pressure shifts the equilibrium towards the side with fewer moles of gas (from 4 moles on reactant side to 2 moles on product side).
Q. 21 Chemistry (Secondary & College Level)
Difficulty: MEDIUM (1 Mark)
In stoichiometry and solution chemistry #7: What is the normality of a 1 M sulfuric acid (H2SO4) solution for neutralization reactions?
A
0.5 N
B
1 N
C
2 N
✓ Correct
D
4 N
💡 Step-by-Step Explanation & Concept Rationale
Normality = Molarity * Basicity. Since H2SO4 is diprotic (basicity = 2), Normality = 1 M * 2 = 2 N.
Q. 22 Chemistry (Secondary & College Level)
Difficulty: MEDIUM (1 Mark)
In stoichiometry and solution chemistry #12: What is the normality of a 1 M sulfuric acid (H2SO4) solution for neutralization reactions?
A
4 N
B
1 N
C
0.5 N
D
2 N
✓ Correct
💡 Step-by-Step Explanation & Concept Rationale
Normality = Molarity * Basicity. Since H2SO4 is diprotic (basicity = 2), Normality = 1 M * 2 = 2 N.
Q. 23 Chemistry (Secondary & College Level)
Difficulty: MEDIUM (1 Mark)
In stoichiometry and solution chemistry #17: What is the normality of a 1 M sulfuric acid (H2SO4) solution for neutralization reactions?
A
2 N
✓ Correct
B
1 N
C
0.5 N
D
4 N
💡 Step-by-Step Explanation & Concept Rationale
Normality = Molarity * Basicity. Since H2SO4 is diprotic (basicity = 2), Normality = 1 M * 2 = 2 N.
Q. 24 Chemistry (Secondary & College Level)
Difficulty: MEDIUM (1 Mark)
In stoichiometry and solution chemistry #22: What is the normality of a 1 M sulfuric acid (H2SO4) solution for neutralization reactions?
A
1 N
B
2 N
✓ Correct
C
0.5 N
D
4 N
💡 Step-by-Step Explanation & Concept Rationale
Normality = Molarity * Basicity. Since H2SO4 is diprotic (basicity = 2), Normality = 1 M * 2 = 2 N.
Q. 25 Chemistry (Secondary & College Level)
Difficulty: MEDIUM (1 Mark)
In stoichiometry and solution chemistry #27: What is the normality of a 1 M sulfuric acid (H2SO4) solution for neutralization reactions?
A
0.5 N
B
1 N
C
2 N
✓ Correct
D
4 N
💡 Step-by-Step Explanation & Concept Rationale
Normality = Molarity * Basicity. Since H2SO4 is diprotic (basicity = 2), Normality = 1 M * 2 = 2 N.
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