Telecommunications, RF & Antennas
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📘 Comprehensive Syllabus & Examination Guide
Telecommunications, RF & Antennas
Official curriculum roadmap, subject/topic distribution, negative marking rules, pacing guidelines, and solved sample questions.
🎯 Mapped Subjects & Topic Question Distribution
Total Question Pool
100%
35 MCQs
Combined Active Syllabus
Telecommunications, RF & Antennas
35 MCQs
Topic Pool
📊 Question Pool Structure
35 MCQs across fundamental, intermediate, and advanced concept tiers.
⚡ Recommended Pacing
45 to 60 seconds per MCQ. Flag complex problems and preserve 10 minutes for final revision.
⚖️ Scoring & Negative Marking
+1 mark per correct answer. In competitive tests with negative marking, -0.25 applies for incorrect guesses.
💡 Strategic Preparation & Exam Hall Guidelines
To maximize your score on Telecommunications, RF & Antennas, candidates are advised to follow a structured three-pass approach. In the First Pass, solve all direct recall and formula-based questions within 30 seconds each to secure foundational marks. In the Second Pass, tackle multi-step analytical and quantitative reasoning problems. In the Third Pass, review marked questions and verify calculations.
Practice with the interactive player below to evaluate your speed and accuracy under real exam pressure. Every question features full mathematical formulas, step-by-step worked solutions, and conceptual explanations vetted by Apex Rankers Academy subject matter specialists.
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Solved Blueprint Examples
Showing 10 solved representative questions
📝 Pre-Rendered Solved Sample Questions & Detailed Solutions
Review the solved problems below to understand question phrasing, answer choices, and step-by-step solution logic prior to starting the full interactive practice drill:
Sample Question 1
Telecommunications, RF & Antennas
Easy • Electronics Engineering
In standard Amplitude Modulation (AM), if the carrier power is Pc and the modulation index is m, what is the total transmitted power Pt?
A
Pt = Pc * (1 + m^2 / 2)
B
Pt = Pc * (1 + m / 2)
C
Pt = Pc * (1 + m^2)
D
Pt = Pc * (1 + 2 * m^2)
✓ Correct Answer: A - Pt = Pc * (1 + m^2 / 2)
📖 Step-by-Step Solution & Conceptual Rationale:
Total power in DSB-FC AM is Pt = Pc + Pusb + Plsb = Pc + Pc*(m^2/4) + Pc*(m^2/4) = Pc * (1 + m^2 / 2).
Sample Question 2
Telecommunications, RF & Antennas
Medium • Electronics Engineering
What is the maximum theoretical transmission efficiency of a standard AM (DSB-FC) broadcast signal with 100% sinusoidal modulation (m = 1)?
A
100%
B
33.33%
C
50%
D
66.67%
✓ Correct Answer: B - 33.33%
📖 Step-by-Step Solution & Conceptual Rationale:
Efficiency eta = (Sideband Power / Total Power) = (m^2 / (2 + m^2)). For m = 1, eta = 1 / 3 ≈ 33.33%. Two-thirds of the power is wasted in the carrier which carries no information.
Sample Question 3
Telecommunications, RF & Antennas
Easy • Electronics Engineering
According to Carson's Rule, what is the approximate transmission bandwidth (BW) of an FM signal with frequency deviation Delta_f and modulating signal bandwidth fm?
A
BW = 2 * (Delta_f + fm)
B
BW = Delta_f + fm
C
BW = 2 * Delta_f * fm
D
BW = 2 * fm
✓ Correct Answer: A - BW = 2 * (Delta_f + fm)
📖 Step-by-Step Solution & Conceptual Rationale:
Carson's Rule states that 98% of FM power is contained within bandwidth BW = 2 * (Delta_f + fm) = 2 * fm * (beta + 1).
Sample Question 4
Telecommunications, RF & Antennas
Easy • Electronics Engineering
In a standard superheterodyne AM broadcast receiver, what is the standard intermediate frequency (IF)?
A
455 kHz
B
10.7 MHz
C
70 MHz
D
1.4 MHz
✓ Correct Answer: A - 455 kHz
📖 Step-by-Step Solution & Conceptual Rationale:
AM broadcast receivers use an IF of 455 kHz. FM broadcast receivers use an IF of 10.7 MHz.
Sample Question 5
Telecommunications, RF & Antennas
Medium • Electronics Engineering
In a superheterodyne receiver with local oscillator frequency fo = fs + IF, what is the image frequency f_image?
A
f_image = fs + IF
B
f_image = fs + 2 * IF
C
f_image = fs - 2 * IF
D
f_image = 2 * fs + IF
✓ Correct Answer: B - f_image = fs + 2 * IF
📖 Step-by-Step Solution & Conceptual Rationale:
An unwanted station at f_image = fs + 2*IF mixes with fo = fs + IF to produce |fo - f_image| = IF, entering the IF amplifier unless attenuated by RF preselector filtering.
Sample Question 6
Telecommunications, RF & Antennas
Easy • Electronics Engineering
Shannon-Hartley theorem states that the channel capacity C (in bits/sec) for a band-limited AWGN channel is:
A
C = B * log2(1 + S/N)
B
C = 2 * B * log2(S/N)
C
C = B * ln(1 + S/N)
D
C = B * (1 + S/N)^2
✓ Correct Answer: A - C = B * log2(1 + S/N)
📖 Step-by-Step Solution & Conceptual Rationale:
Shannon-Hartley theorem: C = B * log2(1 + S/N), where B is channel bandwidth in Hertz and S/N is the signal-to-noise power ratio.
Sample Question 7
Telecommunications, RF & Antennas
Medium • Electronics Engineering
In Pulse Code Modulation (PCM), if the number of quantization bits per sample is increased from n to n + 1, by how many dB does the Signal-to-Quantization-Noise Ratio (SQNR) improve?
A
3 dB
B
6.02 dB
C
10 dB
D
12 dB
✓ Correct Answer: B - 6.02 dB
📖 Step-by-Step Solution & Conceptual Rationale:
SQNR (in dB) ≈ 1.76 + 6.02 * n. Adding 1 bit increases the SQNR by approximately 6.02 dB (a 4-fold increase in SNR power ratio).
Sample Question 8
Telecommunications, RF & Antennas
Medium • Electronics Engineering
What is the primary purpose of companding (compressing-expanding) using A-law or mu-law in digital telephony PCM systems?
A
To increase transmission data rate by 50%
B
To maintain a relatively constant SNR over a wide dynamic range of weak and strong speech signals
C
To eliminate the need for an anti-aliasing filter
D
To convert analog voice signals directly into optical pulses
✓ Correct Answer: B - To maintain a relatively constant SNR over a wide dynamic range of weak and strong speech signals
📖 Step-by-Step Solution & Conceptual Rationale:
Non-uniform quantization (companding) uses smaller step sizes for low amplitude signals and larger step sizes for large signals, keeping SQNR roughly constant across all voice levels.
Sample Question 9
Telecommunications, RF & Antennas
Easy • Electronics Engineering
What is the radiation resistance of an ideal center-fed half-wave dipole antenna in free space?
A
36.5 ohms
B
73.13 ohms
C
50 ohms
D
377 ohms
✓ Correct Answer: B - 73.13 ohms
📖 Step-by-Step Solution & Conceptual Rationale:
The terminal impedance of a resonant half-wave thin dipole in free space is approximately 73.13 + j42.5 ohms (purely resistive ~73 ohms when cut slightly shorter by ~5%).
Sample Question 10
Telecommunications, RF & Antennas
Easy • Electronics Engineering
What is the radiation resistance of an ideal quarter-wave monopole antenna over an infinite, perfectly conducting ground plane?
A
73.13 ohms
B
36.56 ohms
C
120 pi ohms
D
300 ohms
✓ Correct Answer: B - 36.56 ohms
📖 Step-by-Step Solution & Conceptual Rationale:
By image theory, a quarter-wave monopole over a ground plane radiates half the total power of a half-wave dipole for the same current. Thus, its radiation resistance is half: 73.13 / 2 ≈ 36.56 ohms.
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