Official curriculum roadmap, subject/topic distribution, negative marking rules, pacing guidelines, and solved sample questions.
๐ฏ Mapped Subjects & Topic Question Distribution
Total Question Pool100%
10 MCQs
Combined Active Syllabus
LCM
10 MCQs
Topic Pool
๐ Question Pool Structure
10 MCQs across fundamental, intermediate, and advanced concept tiers.
โก Recommended Pacing
45 to 60 seconds per MCQ. Flag complex problems and preserve 10 minutes for final revision.
โ๏ธ Scoring & Negative Marking
+1 mark per correct answer. In competitive tests with negative marking, -0.25 applies for incorrect guesses.
๐ก Strategic Preparation & Exam Hall Guidelines
To maximize your score on LCM, candidates are advised to follow a structured three-pass approach. In the First Pass, solve all direct recall and formula-based questions within 30 seconds each to secure foundational marks. In the Second Pass, tackle multi-step analytical and quantitative reasoning problems. In the Third Pass, review marked questions and verify calculations.
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Sample Question 1
LCMMedium • Quantitative Aptitude Test
What is the least common multiple (LCM) of 3 and 6?
All numbers are powers of 2 ($8 = 2^3$, $16 = 2^4$, $32 = 2^5$). The LCM is the highest power of 2: \[\text{LCM} = 2^5 = 32\] Thus, the correct option is (B).
Sample Question 4
LCMMedium • Quantitative Aptitude Test
What is the least common multiple (LCM) of 6, 12, 24, and 48?
Since 6, 12, and 24 are all divisors of 48, the least common multiple of the set is: \[\text{LCM}(6, 12, 24, 48) = 48\] Thus, the correct option is (C).
Sample Question 5
LCMMedium • Quantitative Aptitude Test
What is the least common multiple (LCM) of 4, 6, and 12?
Find the prime factorizations: \[7 = 7^1\] \[14 = 2^1 \times 7^1\] \[13 = 13^1\] The LCM is the product of the highest powers of all prime factors: \[\text{LCM} = 2^1 \times 7^1 \times 13^1 = 14 \times 13 = 182\] Thus, the correct option is (C).
Sample Question 9
LCMMedium • Quantitative Aptitude Test
What is the Least Common Multiple (LCM) of $2$ and $3$?
Prime factorization: $4 = 2^2$ and $6 = 2 \times 3$. Taking the highest power of each prime factor: \[\text{LCM}(4, 6) = 2^2 \times 3 = 4 \times 3 = 12\] Thus, the correct option is (C).
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