Logic
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๐ Comprehensive Syllabus & Examination Guide
Logic
Official curriculum roadmap, subject/topic distribution, negative marking rules, pacing guidelines, and solved sample questions.
๐ฏ Mapped Subjects & Topic Question Distribution
Total Question Pool
100%
13 MCQs
Combined Active Syllabus
Logic
13 MCQs
Topic Pool
๐ Question Pool Structure
13 MCQs across fundamental, intermediate, and advanced concept tiers.
โก Recommended Pacing
45 to 60 seconds per MCQ. Flag complex problems and preserve 10 minutes for final revision.
โ๏ธ Scoring & Negative Marking
+1 mark per correct answer. In competitive tests with negative marking, -0.25 applies for incorrect guesses.
๐ก Strategic Preparation & Exam Hall Guidelines
To maximize your score on Logic, candidates are advised to follow a structured three-pass approach. In the First Pass, solve all direct recall and formula-based questions within 30 seconds each to secure foundational marks. In the Second Pass, tackle multi-step analytical and quantitative reasoning problems. In the Third Pass, review marked questions and verify calculations.
Practice with the interactive player below to evaluate your speed and accuracy under real exam pressure. Every question features full mathematical formulas, step-by-step worked solutions, and conceptual explanations vetted by Apex Rankers Academy subject matter specialists.
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Solved Blueprint Examples
Showing 10 solved representative questions
๐ Pre-Rendered Solved Sample Questions & Detailed Solutions
Review the solved problems below to understand question phrasing, answer choices, and step-by-step solution logic prior to starting the full interactive practice drill:
Sample Question 1
Logic
Hard • Computer Aptitude Test
The least significant bit of the binary number, which is equivalent to any odd decimal number, is:
A
False
B
1
C
1 or 0
D
True
โ Correct Answer: D - True
๐ Step-by-Step Solution & Conceptual Rationale:
All odd integers in binary end with 1 in the 20 position.
Sample Question 2
Logic
Hard • Computer Aptitude Test
Binary circuit elements have:
A
One stable state
B
Two stable state
C
Three stable state
D
None of above
โ Correct Answer: B - Two stable state
๐ Step-by-Step Solution & Conceptual Rationale:
Binary logic is based on two states: 0 (off) and 1 (on).
Sample Question 3
Logic
Hard • Computer Aptitude Test
EBCDIC can code up to how many different characters?
A
256
B
16
C
32
D
64
โ Correct Answer: A - 256
๐ Step-by-Step Solution & Conceptual Rationale:
The 8-bit EBCDIC code supports 28=256 unique character representations.
Sample Question 4
Logic
Hard • Computer Aptitude Test
The computer code for the interchange of information between terminals is:
A
ASCII
B
BCD
C
EBCDIC
D
All of above
โ Correct Answer: A - ASCII
๐ Step-by-Step Solution & Conceptual Rationale:
American Standard Code for Information Interchange is the global standard for terminal data.
Sample Question 5
Logic
Hard • Computer Aptitude Test
If in a computer, 16 bits are used to specify address in a RAM, the number of addresses will be:
A
216
B
65536
C
64K
D
Any above
โ Correct Answer: D - Any above
๐ Step-by-Step Solution & Conceptual Rationale:
Calculation: 216=65,536.
To find the number of unique memory addresses that can be generated using a given number of address bits, we use the formula: $(\text{Number of addresses}=2^{n})$ Where \(n\) is the number of bits. Given \(n = 16\):
A ($2^{16}$): This represents the direct mathematical expression of the formula (\(2^{16}\)). (Note: In many standard digital electronics multiple-choice questionnaires, option A is printed as "216" due to a typo omitting the superscript formatting for $(2^{16})$).
B (65536): Evaluating the exponential formula gives exactly \(2 \times 2 \times 2 \dots = 65,536\) unique addressable locations.
C (64K): In computer memory architecture, \(1\text{ K}\) (Kilobyte/Kibi) is equal to $(2^{10} = 1,024)$. Dividing our total addresses by this unit gives:
$$(\frac{65,536}{1,024}=64)$$
To find the number of unique memory addresses that can be generated using a given number of address bits, we use the formula: $(\text{Number of addresses}=2^{n})$ Where \(n\) is the number of bits. Given \(n = 16\):
A ($2^{16}$): This represents the direct mathematical expression of the formula (\(2^{16}\)). (Note: In many standard digital electronics multiple-choice questionnaires, option A is printed as "216" due to a typo omitting the superscript formatting for $(2^{16})$).
B (65536): Evaluating the exponential formula gives exactly \(2 \times 2 \times 2 \dots = 65,536\) unique addressable locations.
C (64K): In computer memory architecture, \(1\text{ K}\) (Kilobyte/Kibi) is equal to $(2^{10} = 1,024)$. Dividing our total addresses by this unit gives:
$$(\frac{65,536}{1,024}=64)$$
Sample Question 6
Logic
Hard • Computer Aptitude Test
Which number system is commonly used as a shortcut notation for groups of four binary digits?
A
Binary
B
Decimal
C
Octal
D
Hexadecimal
โ Correct Answer: D - Hexadecimal
๐ Step-by-Step Solution & Conceptual Rationale:
Hex uses one character (0-F) to represent 4 bits (24=16).
Sample Question 7
Logic
Hard • Computer Aptitude Test
A technique used by codes to convert an analog signal into a digital bit stream is known as:
A
Pulse code modulation
B
Pulse stretcher
C
Query processing
D
Queue management
โ Correct Answer: A - Pulse code modulation
๐ Step-by-Step Solution & Conceptual Rationale:
PCM is the standard method for digitally representing analog signals.
Sample Question 8
Logic
Hard • Computer Aptitude Test
The original ASCII code used.. bits of each byte, reserving that last bit for error checking:
A
5
B
6
C
7
D
8
โ Correct Answer: C - 7
๐ Step-by-Step Solution & Conceptual Rationale:
Standard ASCII is a 7-bit code; the 8th bit was often a parity bit.
Sample Question 9
Logic
Hard • Computer Aptitude Test
EBCDIC is:
A
6-bit coding system
B
7-bit coding system
C
8-bitcoding system
D
9 bit coding system
โ Correct Answer: C - 8-bitcoding system
๐ Step-by-Step Solution & Conceptual Rationale:
Extended Binary Coded Decimal Interchange Code is a standard 8-bit character encoding.
Sample Question 10
Logic
Hard • Computer Aptitude Test
Extended ASCII uses:
A
8 bits for coding
B
9 bits for coding
C
10 bits for coding
D
11 bits for coding
โ Correct Answer: A - 8 bits for coding
๐ Step-by-Step Solution & Conceptual Rationale:
Extended ASCII expands the standard 7-bit set to 8 bits to include additional characters.
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