Distance

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๐Ÿ“˜ Comprehensive Syllabus & Examination Guide

Distance

Official curriculum roadmap, subject/topic distribution, negative marking rules, pacing guidelines, and solved sample questions.

๐ŸŽฏ Mapped Subjects & Topic Question Distribution

Total Question Pool 100%
5 MCQs
Combined Active Syllabus
Distance
5 MCQs
Topic Pool
๐Ÿ“Š Question Pool Structure
5 MCQs across fundamental, intermediate, and advanced concept tiers.
โšก Recommended Pacing
45 to 60 seconds per MCQ. Flag complex problems and preserve 10 minutes for final revision.
โš–๏ธ Scoring & Negative Marking
+1 mark per correct answer. In competitive tests with negative marking, -0.25 applies for incorrect guesses.

๐Ÿ’ก Strategic Preparation & Exam Hall Guidelines

To maximize your score on Distance, candidates are advised to follow a structured three-pass approach. In the First Pass, solve all direct recall and formula-based questions within 30 seconds each to secure foundational marks. In the Second Pass, tackle multi-step analytical and quantitative reasoning problems. In the Third Pass, review marked questions and verify calculations.

Practice with the interactive player below to evaluate your speed and accuracy under real exam pressure. Every question features full mathematical formulas, step-by-step worked solutions, and conceptual explanations vetted by Apex Rankers Academy subject matter specialists.

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Solved Blueprint Examples

๐Ÿ“ Pre-Rendered Solved Sample Questions & Detailed Solutions

Showing 5 solved representative questions

Review the solved problems below to understand question phrasing, answer choices, and step-by-step solution logic prior to starting the full interactive practice drill:

Sample Question 1
Distance Hard • Quantitative Aptitude Test
A passenger train traveling at 36 km/h leaves a station at 11:00 AM. An express train traveling at 48 km/h follows it on a parallel track departing at 5:00 PM. In how many hours after 5:00 PM will the express train overtake the passenger train?
A 12 hours
B 15 hours
C 18 hours
D 24 hours
โœ“ Correct Answer: C - 18 hours
๐Ÿ“– Step-by-Step Solution & Conceptual Rationale:
The time difference is from 11:00 AM to 5:00 PM $= 6\text{ hours}$. The lead distance accumulated by the passenger train is: \[36\text{ km/h} \times 6\text{ h} = 216\text{ km}\] The relative speed of the express train is: \[48 - 36 = 12\text{ km/h}\] Time taken to overtake: \[\text{Time} = \frac{216}{12} = 18\text{ hours}\] Thus, the correct option is (C).
Sample Question 2
Distance Hard • Quantitative Aptitude Test
Ali walks from his house to the railway station. If he walks at 3 km/h, he misses the train by 4 minutes. If he walks at 4 km/h, he arrives 6 minutes before the departure. What is the distance from his house to the station?
A 1.5 km
B 2 km
C 2.5 km
D 3 km
โœ“ Correct Answer: B - 2 km
๐Ÿ“– Step-by-Step Solution & Conceptual Rationale:
The total difference in arrival times is: \[4\text{ min (late)} - (-6\text{ min (early)}) = 10\text{ minutes} = \frac{10}{60} = \frac{1}{6}\text{ hour}\] Let the distance be $d\text{ km}$: \[\frac{d}{3} - \frac{d}{4} = \frac{1}{6} \implies \frac{4d - 3d}{12} = \frac{1}{6} \implies \frac{d}{12} = \frac{1}{6} \implies d = 2\text{ km}\] Thus, the correct option is (B).
Sample Question 3
Distance Hard • Quantitative Aptitude Test
A hound pursues a hare: 3 leaps of the hound equal 4 leaps of the hare in time. If 3 leaps of the hound cover 9 m and 4 leaps of the hare cover 8 m, what distance does the hound gain over the hare in one leap cycle?
A 0.5 m
B 1 m
C 1.5 m
D 2 m
โœ“ Correct Answer: B - 1 m
๐Ÿ“– Step-by-Step Solution & Conceptual Rationale:
In one cycle, the hound covers 9 m and the hare covers 8 m. The relative distance gained by the hound in one cycle is: \[9\text{ m} - 8\text{ m} = 1\text{ m}\] Thus, the correct option is (B).
Sample Question 4
Distance Hard • Quantitative Aptitude Test
A monkey climbs 10 m up a greased pole in the first minute and slips down 3 m in the second minute. How long will it take to reach the top of a 63-meter pole?
A 15 min 30 sec
B 16 min 42 sec
C 17 min 15 sec
D 18 min
โœ“ Correct Answer: B - 16 min 42 sec
๐Ÿ“– Step-by-Step Solution & Conceptual Rationale:
In every 2-minute cycle, the net ascent is $10 - 3 = 7\text{ m}$. In 14 minutes (7 cycles), net ascent is $7 \times 7 = 49\text{ m}$. In the 15th minute, it climbs 10 m to reach $49 + 10 = 59\text{ m}$. In the 16th minute, it slips back 3 m to $56\text{ m}$. To climb the remaining $63 - 56 = 7\text{ m}$ at the rate of $10\text{ m/min}$: \[\text{Time} = \frac{7}{10}\text{ min} = \frac{7}{10} \times 60\text{ sec} = 42\text{ seconds}\] Total time = $16\text{ min } 42\text{ sec}$. Thus, the correct option is (B).
Sample Question 5
Distance Hard • Quantitative Aptitude Test
Aslam ran around a $\frac{1}{4}\text{ km}$ track 17 times. How many kilometers did he run in total?
A $4\frac{1}{4}\text{ km}$
B $4\text{ km}$
C $4\frac{1}{2}\text{ km}$
D $4\frac{3}{4}\text{ km}$
โœ“ Correct Answer: A - $4\frac{1}{4}\text{ km}$
๐Ÿ“– Step-by-Step Solution & Conceptual Rationale:
Multiply the track length by the number of laps: \[\text{Total Distance} = 17 \times \frac{1}{4}\text{ km} = \frac{17}{4}\text{ km}\] Converting $\frac{17}{4}$ into a mixed fraction: \[\frac{17}{4} = 4\frac{1}{4}\text{ km}\] Thus, the correct option is (A).
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