Finance
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📘 Comprehensive Syllabus & Examination Guide
Finance
Official curriculum roadmap, subject/topic distribution, negative marking rules, pacing guidelines, and solved sample questions.
🎯 Mapped Subjects & Topic Question Distribution
Total Question Pool
100%
12 MCQs
Combined Active Syllabus
Finance
12 MCQs
Topic Pool
📊 Question Pool Structure
12 MCQs across fundamental, intermediate, and advanced concept tiers.
⚡ Recommended Pacing
45 to 60 seconds per MCQ. Flag complex problems and preserve 10 minutes for final revision.
⚖️ Scoring & Negative Marking
+1 mark per correct answer. In competitive tests with negative marking, -0.25 applies for incorrect guesses.
💡 Strategic Preparation & Exam Hall Guidelines
To maximize your score on Finance, candidates are advised to follow a structured three-pass approach. In the First Pass, solve all direct recall and formula-based questions within 30 seconds each to secure foundational marks. In the Second Pass, tackle multi-step analytical and quantitative reasoning problems. In the Third Pass, review marked questions and verify calculations.
Practice with the interactive player below to evaluate your speed and accuracy under real exam pressure. Every question features full mathematical formulas, step-by-step worked solutions, and conceptual explanations vetted by Apex Rankers Academy subject matter specialists.
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Showing 10 solved representative questions
📝 Pre-Rendered Solved Sample Questions & Detailed Solutions
Review the solved problems below to understand question phrasing, answer choices, and step-by-step solution logic prior to starting the full interactive practice drill:
Sample Question 1
Finance
Medium • Quantitative Aptitude Test
After a 22 percent deduction. A's net salary is Rs. 1,600. A's gross salary is nearly
A
Rs. 2,000
B
Rs. 2,025
C
Rs. 2,051
D
Rs. 2,078
✓ Correct Answer: C - Rs. 2,051
📖 Step-by-Step Solution & Conceptual Rationale:
Let the gross salary be $G$.
A $22\%$ deduction leaves $100\% - 22\% = 78\%$ of the gross salary.
\[ 0.78 \times G = 1600 \]
\[ G = \frac{1600}{0.78} \approx \text{Rs. } 2,051.28 \]
Therefore, the gross salary is nearly Rs. 2,051.
A $22\%$ deduction leaves $100\% - 22\% = 78\%$ of the gross salary.
\[ 0.78 \times G = 1600 \]
\[ G = \frac{1600}{0.78} \approx \text{Rs. } 2,051.28 \]
Therefore, the gross salary is nearly Rs. 2,051.
Sample Question 2
Finance
Hard • Quantitative Aptitude Test
Aslam purchased a Chair for Rs. 2,000 and sold it to Arshad at a loss of 10 percent Arshad sold it to Akbar at a loss of 10 percent while Akbar sold it to Qumar at a gain of 10 percent. The amount Qumar paid for it would be Rs......
A
1980
B
1890
C
1782
D
1872
✓ Correct Answer: C - 1782
📖 Step-by-Step Solution & Conceptual Rationale:
We can track the value of the chair through each successive transaction:
Aslam sells to Arshad at a 10% loss:
Price paid by Arshad = \(2000 \times (1 - 0.10) = 2000 \times 0.90 = \mathbf{\text{Rs. 1,800}}\)
Arshad sells to Akbar at a 10% loss:
Price paid by Akbar = \(1800 \times (1 - 0.10) = 1800 \times 0.90 = \mathbf{\text{Rs. 1,620}}\)
Akbar sells to Qumar at a 10% gain:
Price paid by Qumar = \(1620 \times (1 + 0.10) = 1620 \times 1.10 = \mathbf{\text{Rs. 1,782}}\)
Aslam sells to Arshad at a 10% loss:
Price paid by Arshad = \(2000 \times (1 - 0.10) = 2000 \times 0.90 = \mathbf{\text{Rs. 1,800}}\)
Arshad sells to Akbar at a 10% loss:
Price paid by Akbar = \(1800 \times (1 - 0.10) = 1800 \times 0.90 = \mathbf{\text{Rs. 1,620}}\)
Akbar sells to Qumar at a 10% gain:
Price paid by Qumar = \(1620 \times (1 + 0.10) = 1620 \times 1.10 = \mathbf{\text{Rs. 1,782}}\)
Sample Question 3
Finance
Medium • Quantitative Aptitude Test
Ali bought a electric fan priced at Rs. 2,000. He was given two successive discounts of 10 and 5 percent. If he had to pay 10 percent sales tax, the net amount he paid was.
A
Rs. 2,633.40
B
Rs. 2,592
C
Rs. 2,660
D
Rs. 1,881
✓ Correct Answer: D - Rs. 1,881
📖 Step-by-Step Solution & Conceptual Rationale:
Apply the first discount (10%):
Discount amount = \(2,000 \times 0.10 = \text{Rs. 200}\)
Price after 1st discount = \(2,000 - 200 = \text{Rs. 1,800}\)
Apply the second discount (5%) to the reduced price:
Discount amount = \(1,800 \times 0.05 = \text{Rs. 90}\)
Price after 2nd discount = \(1,800 - 90 = \text{Rs. 1,710}\)
Add the 10% sales tax to the final discounted price:
Sales tax amount = \(1,710 \times 0.10 = \text{Rs. 171}\)
Net amount paid = \(1,710 + 171 = \mathbf{\text{Rs. 1,881}}\)
Discount amount = \(2,000 \times 0.10 = \text{Rs. 200}\)
Price after 1st discount = \(2,000 - 200 = \text{Rs. 1,800}\)
Apply the second discount (5%) to the reduced price:
Discount amount = \(1,800 \times 0.05 = \text{Rs. 90}\)
Price after 2nd discount = \(1,800 - 90 = \text{Rs. 1,710}\)
Add the 10% sales tax to the final discounted price:
Sales tax amount = \(1,710 \times 0.10 = \text{Rs. 171}\)
Net amount paid = \(1,710 + 171 = \mathbf{\text{Rs. 1,881}}\)
Sample Question 4
Finance
Hard • Quantitative Aptitude Test
A man sells a radio and a mixer for Rs. 350 each. On one he gains 10 percent and on the other loses 10 percent. Thus on the whole, he
A
Gains nearly 0.1 percent.
B
Neither gains nor loses
C
Loses nearly 1 percent
D
Gains nearly 1 percent
✓ Correct Answer: C - Loses nearly 1 percent
📖 Step-by-Step Solution & Conceptual Rationale:
When two items are sold at the same price—one at a gain of \(x\%\) and the other at a loss of \(x\%\), the overall transaction always results in a loss. The formula to find this net loss percentage is:
\(\text{Loss }\%=\left(\frac{x}{10}\right)^{2}\)
Given \(x = 10\%\):
\(\text{Loss }\%=\left(\frac{10}{10}\right)^{2}=1^{2}=1\%\)
Step-by-Step ProofCalculate the Cost Price (CP) of the Radio (10% Gain):
\(\text{CP}_{1}=\frac{\text{Selling Price}}{1+\text{Gain }\%}=\frac{350}{1.10}=\text{Rs. }318.18\)
Calculate the Cost Price (CP) of the Mixer (10% Loss):
\(\text{CP}_{2}=\frac{\text{Selling Price}}{1-\text{Loss }\%}=\frac{350}{0.90}=\text{Rs. }388.89\)
Find the Totals:Total Cost Price:
\(\text{Rs. } 318.18 + \text{Rs. } 388.89 = \text{Rs. } 707.07\)
Total Selling Price:
\(\text{Rs. } 350 + \text{Rs. } 350 = \text{Rs. } 700.00\)
Calculate Net Loss Percentage:
\(\text{Net Loss}=\text{Rs. }707.07-\text{Rs. }700.00=\text{Rs. }7.07\)
\(\text{Loss }\%=\left(\frac{7.07}{707.07}\right)\times 100=1\%\)
\(\text{Loss }\%=\left(\frac{x}{10}\right)^{2}\)
Given \(x = 10\%\):
\(\text{Loss }\%=\left(\frac{10}{10}\right)^{2}=1^{2}=1\%\)
Step-by-Step ProofCalculate the Cost Price (CP) of the Radio (10% Gain):
\(\text{CP}_{1}=\frac{\text{Selling Price}}{1+\text{Gain }\%}=\frac{350}{1.10}=\text{Rs. }318.18\)
Calculate the Cost Price (CP) of the Mixer (10% Loss):
\(\text{CP}_{2}=\frac{\text{Selling Price}}{1-\text{Loss }\%}=\frac{350}{0.90}=\text{Rs. }388.89\)
Find the Totals:Total Cost Price:
\(\text{Rs. } 318.18 + \text{Rs. } 388.89 = \text{Rs. } 707.07\)
Total Selling Price:
\(\text{Rs. } 350 + \text{Rs. } 350 = \text{Rs. } 700.00\)
Calculate Net Loss Percentage:
\(\text{Net Loss}=\text{Rs. }707.07-\text{Rs. }700.00=\text{Rs. }7.07\)
\(\text{Loss }\%=\left(\frac{7.07}{707.07}\right)\times 100=1\%\)
Sample Question 5
Finance
Medium • Quantitative Aptitude Test
Three successive discounts of 10 percent are equivalent to a single discount of ___ percent.
A
33.2
B
30
C
27.1
D
28.4
✓ Correct Answer: C - 27.1
📖 Step-by-Step Solution & Conceptual Rationale:
Assume the initial price is 100.
First discount (10%):
\(100 - 10 = 90\)
Second discount (10% of 90):
\(90 - 9 = 81\)
Third discount (10% of 81):
\(81 - 8.1 = 72.9\)
Total equivalent discount:
\(100 - 72.9 = 27.1\)
First discount (10%):
\(100 - 10 = 90\)
Second discount (10% of 90):
\(90 - 9 = 81\)
Third discount (10% of 81):
\(81 - 8.1 = 72.9\)
Total equivalent discount:
\(100 - 72.9 = 27.1\)
Sample Question 6
Finance
Hard • Quantitative Aptitude Test
A dealer marks his goods 20 percent above his cost price. If he gives a discount of 10 percent on his marked price, the profit he earns on his good is --- percent.
A
12
B
7.5
C
8
D
10
✓ Correct Answer: C - 8
📖 Step-by-Step Solution & Conceptual Rationale:
Let CP=100
MP=100+20=120
SP=$120\times\frac{(100-10)}{100}=108$.
Profit = 8%.
MP=100+20=120
SP=$120\times\frac{(100-10)}{100}=108$.
Profit = 8%.
Sample Question 7
Finance
Hard • Quantitative Aptitude Test
A man buys a scooter for Rs. 7,000 and sells it for Rs. 11,500. The percentage profit is nearly ------ percent.
A
70.6
B
54
C
58
D
64.3
✓ Correct Answer: D - 64.3
📖 Step-by-Step Solution & Conceptual Rationale:
Find the profit amount: \(\text{Selling Price} - \text{Cost Price} = 11,500 - 7,000 =\) Rs. 4,500.
Calculate the profit percentage:
\(\text{Profit }\%=\left(\frac{\text{Profit}}{\text{Cost Price}}\right)\times 100\)
\(\text{Profit }\%=\left(\frac{4,500}{7,000}\right)\times 100\approx 64.28\%\)
When rounded to the nearest tenth, it gives 64.3%.
Calculate the profit percentage:
\(\text{Profit }\%=\left(\frac{\text{Profit}}{\text{Cost Price}}\right)\times 100\)
\(\text{Profit }\%=\left(\frac{4,500}{7,000}\right)\times 100\approx 64.28\%\)
When rounded to the nearest tenth, it gives 64.3%.
Sample Question 8
Finance
Hard • Quantitative Aptitude Test
If Rs. 1200 yields Rs. 594 as interest for six years at simple interest, the interest rate would be nearly ------ percent.
A
7.25
B
8.25
C
9
D
6
✓ Correct Answer: B - 8.25
📖 Step-by-Step Solution & Conceptual Rationale:
Simple Interest Formula: \(SI = \frac{P \times R \times T}{100}\)
Given values:
Principal (\(P\)) = Rs. 1200
Simple Interest (\(SI\)) = Rs. 594
Time (\(T\)) = 6 years
Rearrange the formula to solve for Rate (\(R\)):
\(R=\frac{SI\times 100}{P\times T}\)
\(R=\frac{594\times 100}{1200\times 6}\)
\(R=\frac{59400}{7200}=8.25\%\)
Given values:
Principal (\(P\)) = Rs. 1200
Simple Interest (\(SI\)) = Rs. 594
Time (\(T\)) = 6 years
Rearrange the formula to solve for Rate (\(R\)):
\(R=\frac{SI\times 100}{P\times T}\)
\(R=\frac{594\times 100}{1200\times 6}\)
\(R=\frac{59400}{7200}=8.25\%\)
Sample Question 9
Finance
Medium • Quantitative Aptitude Test
Rs. 2,000 at 5 percent compound interest after four years will become nearly.
A
Rs. 2,370
B
Rs. 2,430
C
Rs. 2,200
D
Rs. 2,500
✓ Correct Answer: B - Rs. 2,430
📖 Step-by-Step Solution & Conceptual Rationale:
Compound Interest Formula: \(A = P \left(1 + \frac{R}{100}\right)^T\)
Given values:
Principal (\(P\)) = Rs. 2,000
Rate (\(R\)) = 5%
Time (\(T\)) = 4 years
Calculate the amount:
\(A=2000\times \left(1+0.05\right)^{4}\)
\(A=2000\times (1.05)^{4}\)
\(A=2000\times 1.2155\approx \text{Rs. }2431.01\)
When rounded to the closest option, it gives Rs. 2,430.
Given values:
Principal (\(P\)) = Rs. 2,000
Rate (\(R\)) = 5%
Time (\(T\)) = 4 years
Calculate the amount:
\(A=2000\times \left(1+0.05\right)^{4}\)
\(A=2000\times (1.05)^{4}\)
\(A=2000\times 1.2155\approx \text{Rs. }2431.01\)
When rounded to the closest option, it gives Rs. 2,430.
Sample Question 10
Finance
Medium • Quantitative Aptitude Test
-- -- -- becomes Rs. 2,500 in four years at $6\frac{1}{4}$ percent, simple interest.
A
1800
B
2000
C
1500
D
2200
✓ Correct Answer: B - 2000
📖 Step-by-Step Solution & Conceptual Rationale:
Convert the rate to a decimal: \(6\frac{1}{4}\% = 6.25\%\) per year.
Calculate total interest percentage over 4 years:
\(6.25\% \times 4 \text{ years} = 25\%\).
Set up the amount formula:
The total amount (\(A\)) equals the Principal (\(P\)) plus \(25\%\) of the Principal.
\(A=P+0.25P=1.25P\)
Solve for Principal (\(P\)):
\(2500=1.25P\)
\(P=\frac{2500}{1.25}=2000\)
Calculate total interest percentage over 4 years:
\(6.25\% \times 4 \text{ years} = 25\%\).
Set up the amount formula:
The total amount (\(A\)) equals the Principal (\(P\)) plus \(25\%\) of the Principal.
\(A=P+0.25P=1.25P\)
Solve for Principal (\(P\)):
\(2500=1.25P\)
\(P=\frac{2500}{1.25}=2000\)
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