📚 Model Test for: Chapter 12: Data Handling — Comprehensive Solved Notes & Solution Manual
⏱️ Official Timed Examination

Class 8 Mathematics - Ch 12: Data Handling Chapter Mock Test

Class: 8 | Subject: Mathematics | Board: Federal Board of Intermediate and Secondary Education (FBISE)

Duration
⏱️ 35 Mins
Question Pool
📝 25 MCQs
Passing Benchmark
🎯 50.0%
Scoring Engine
✓ Instant & Ranked

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Sample Questions & Solved Explanations

Representative sample from official examination pool

Below are representative questions drawn directly from the testing blueprint for this exam. Review these worked examples to understand the question style, difficulty calibration, and grading criteria:

Sample Q1 (Short Question) Difficulty: Easy
Determine whether (6, 8, 10) is a Pythagorean triple.
✓ Answer: Yes, (6, 8, 10) is a Pythagorean triple.
Given numbers: 6, 8, 10 Let a = 6, b = 8, and the longest side c = 10. Calculate sum of squares of smaller sides: a² + b² = 6² + 8² = 36 + 64 = 100 Calculate square of largest side: c² = 10² = 100 Since a² + b² = c² (100 = 100), the numbers satisfy Pythagoras Theorem. Conclusion: (6, 8, 10) is a Pythagorean triple.
Sample Q2 (Short Question) Difficulty: Easy
Determine whether (5, 7, 10) is a Pythagorean triple.
✓ Answer: No, (5, 7, 10) is not a Pythagorean triple.
Given numbers: 5, 7, 10 Let a = 5, b = 7, c = 10. a² + b² = 5² + 7² = 25 + 49 = 74 c² = 10² = 100 Since 74 ≠ 100 (a² + b² ≠ c²), it does not obey Pythagoras Theorem. Conclusion: (5, 7, 10) is not a Pythagorean triple.
Sample Q3 (Short Question) Difficulty: Easy
Determine whether (5, 12, 13) is a Pythagorean triple.
✓ Answer: Yes, (5, 12, 13) is a Pythagorean triple.
Given numbers: 5, 12, 13 Let a = 5, b = 12, c = 13. a² + b² = 5² + 12² = 25 + 144 = 169 c² = 13² = 169 Since a² + b² = c², the triple satisfies the theorem. Conclusion: (5, 12, 13) is a Pythagorean triple.
Sample Q4 (Short Question) Difficulty: Easy
Determine whether (1, 1, √2) is a Pythagorean triple.
✓ Answer: Yes, (1, 1, √2) satisfies the Pythagoras theorem.
Given numbers: 1, 1, √2 Let a = 1, b = 1, c = √2. a² + b² = 1² + 1² = 1 + 1 = 2 c² = (√2)² = 2 Since a² + b² = c² (2 = 2), the relation holds true. Conclusion: (1, 1, √2) satisfies the theorem.
Sample Q5 (Short Question) Difficulty: Easy
Determine whether (12, 16, 20) is a Pythagorean triple.
✓ Answer: Yes, (12, 16, 20) is a Pythagorean triple.
Given numbers: 12, 16, 20 a² + b² = 12² + 16² = 144 + 256 = 400 c² = 20² = 400 Since 400 = 400, (12, 16, 20) is a Pythagorean triple.
Sample Q6 (Short Question) Difficulty: Easy
Determine whether (5, √5, 30) is a Pythagorean triple.
✓ Answer: No, (5, √5, 30) is not a Pythagorean triple.
Given numbers: 5, √5, 30 a² + b² = 5² + (√5)² = 25 + 5 = 30 c² = 30² = 900 Since 30 ≠ 900, it is not a Pythagorean triple.
Sample Q7 (Short Question) Difficulty: Easy
Determine whether (√3, √5, 2√2) is a Pythagorean triple.
✓ Answer: Yes, (√3, √5, 2√2) satisfies the Pythagoras theorem.
Given numbers: √3, √5, 2√2 a² + b² = (√3)² + (√5)² = 3 + 5 = 8 c² = (2√2)² = 4 × 2 = 8 Since 8 = 8, the relation holds true.
Sample Q8 (Short Question) Difficulty: Easy
Determine whether (8, 10, 12) is a Pythagorean triple.
✓ Answer: No, (8, 10, 12) is not a Pythagorean triple.
Given numbers: 8, 10, 12 a² + b² = 8² + 10² = 64 + 100 = 164 c² = 12² = 144 Since 164 ≠ 144, it is not a Pythagorean triple.
Sample Q9 (Short Question) Difficulty: Easy
In a right-angled triangle ABC where ∠C = 90°, find the hypotenuse c if a = 8 cm and b = 6 cm.
✓ Answer: 10 cm
In right triangle ABC with ∠C = 90°: c² = a² + b² c² = 8² + 6² = 64 + 36 = 100 c = √100 = 10 cm Answer: c = 10 cm.
Sample Q10 (Short Question) Difficulty: Easy
In a right-angled triangle ABC where ∠C = 90°, find side b if a = 4 cm and c = √32 cm.
✓ Answer: 4 cm
By Pythagoras theorem: c² = a² + b² (√32)² = 4² + b² 32 = 16 + b² b² = 32 - 16 = 16 b = √16 = 4 cm Answer: b = 4 cm.